3.1.57 \(\int x^3 (a+b x^2)^5 \, dx\)

Optimal. Leaf size=34 \[ \frac {\left (a+b x^2\right )^7}{14 b^2}-\frac {a \left (a+b x^2\right )^6}{12 b^2} \]

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Rubi [A]  time = 0.04, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {266, 43} \begin {gather*} \frac {\left (a+b x^2\right )^7}{14 b^2}-\frac {a \left (a+b x^2\right )^6}{12 b^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^3*(a + b*x^2)^5,x]

[Out]

-(a*(a + b*x^2)^6)/(12*b^2) + (a + b*x^2)^7/(14*b^2)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int x^3 \left (a+b x^2\right )^5 \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int x (a+b x)^5 \, dx,x,x^2\right )\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \left (-\frac {a (a+b x)^5}{b}+\frac {(a+b x)^6}{b}\right ) \, dx,x,x^2\right )\\ &=-\frac {a \left (a+b x^2\right )^6}{12 b^2}+\frac {\left (a+b x^2\right )^7}{14 b^2}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 66, normalized size = 1.94 \begin {gather*} \frac {a^5 x^4}{4}+\frac {5}{6} a^4 b x^6+\frac {5}{4} a^3 b^2 x^8+a^2 b^3 x^{10}+\frac {5}{12} a b^4 x^{12}+\frac {b^5 x^{14}}{14} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^3*(a + b*x^2)^5,x]

[Out]

(a^5*x^4)/4 + (5*a^4*b*x^6)/6 + (5*a^3*b^2*x^8)/4 + a^2*b^3*x^10 + (5*a*b^4*x^12)/12 + (b^5*x^14)/14

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^3 \left (a+b x^2\right )^5 \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x^3*(a + b*x^2)^5,x]

[Out]

IntegrateAlgebraic[x^3*(a + b*x^2)^5, x]

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fricas [A]  time = 0.81, size = 56, normalized size = 1.65 \begin {gather*} \frac {1}{14} x^{14} b^{5} + \frac {5}{12} x^{12} b^{4} a + x^{10} b^{3} a^{2} + \frac {5}{4} x^{8} b^{2} a^{3} + \frac {5}{6} x^{6} b a^{4} + \frac {1}{4} x^{4} a^{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(b*x^2+a)^5,x, algorithm="fricas")

[Out]

1/14*x^14*b^5 + 5/12*x^12*b^4*a + x^10*b^3*a^2 + 5/4*x^8*b^2*a^3 + 5/6*x^6*b*a^4 + 1/4*x^4*a^5

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giac [A]  time = 1.18, size = 56, normalized size = 1.65 \begin {gather*} \frac {1}{14} \, b^{5} x^{14} + \frac {5}{12} \, a b^{4} x^{12} + a^{2} b^{3} x^{10} + \frac {5}{4} \, a^{3} b^{2} x^{8} + \frac {5}{6} \, a^{4} b x^{6} + \frac {1}{4} \, a^{5} x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(b*x^2+a)^5,x, algorithm="giac")

[Out]

1/14*b^5*x^14 + 5/12*a*b^4*x^12 + a^2*b^3*x^10 + 5/4*a^3*b^2*x^8 + 5/6*a^4*b*x^6 + 1/4*a^5*x^4

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maple [A]  time = 0.00, size = 57, normalized size = 1.68 \begin {gather*} \frac {1}{14} b^{5} x^{14}+\frac {5}{12} a \,b^{4} x^{12}+a^{2} b^{3} x^{10}+\frac {5}{4} a^{3} b^{2} x^{8}+\frac {5}{6} a^{4} b \,x^{6}+\frac {1}{4} a^{5} x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(b*x^2+a)^5,x)

[Out]

1/14*b^5*x^14+5/12*a*b^4*x^12+a^2*b^3*x^10+5/4*a^3*b^2*x^8+5/6*a^4*b*x^6+1/4*a^5*x^4

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maxima [A]  time = 1.36, size = 56, normalized size = 1.65 \begin {gather*} \frac {1}{14} \, b^{5} x^{14} + \frac {5}{12} \, a b^{4} x^{12} + a^{2} b^{3} x^{10} + \frac {5}{4} \, a^{3} b^{2} x^{8} + \frac {5}{6} \, a^{4} b x^{6} + \frac {1}{4} \, a^{5} x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(b*x^2+a)^5,x, algorithm="maxima")

[Out]

1/14*b^5*x^14 + 5/12*a*b^4*x^12 + a^2*b^3*x^10 + 5/4*a^3*b^2*x^8 + 5/6*a^4*b*x^6 + 1/4*a^5*x^4

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mupad [B]  time = 0.02, size = 56, normalized size = 1.65 \begin {gather*} \frac {a^5\,x^4}{4}+\frac {5\,a^4\,b\,x^6}{6}+\frac {5\,a^3\,b^2\,x^8}{4}+a^2\,b^3\,x^{10}+\frac {5\,a\,b^4\,x^{12}}{12}+\frac {b^5\,x^{14}}{14} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a + b*x^2)^5,x)

[Out]

(a^5*x^4)/4 + (b^5*x^14)/14 + (5*a^4*b*x^6)/6 + (5*a*b^4*x^12)/12 + (5*a^3*b^2*x^8)/4 + a^2*b^3*x^10

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sympy [B]  time = 0.08, size = 63, normalized size = 1.85 \begin {gather*} \frac {a^{5} x^{4}}{4} + \frac {5 a^{4} b x^{6}}{6} + \frac {5 a^{3} b^{2} x^{8}}{4} + a^{2} b^{3} x^{10} + \frac {5 a b^{4} x^{12}}{12} + \frac {b^{5} x^{14}}{14} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(b*x**2+a)**5,x)

[Out]

a**5*x**4/4 + 5*a**4*b*x**6/6 + 5*a**3*b**2*x**8/4 + a**2*b**3*x**10 + 5*a*b**4*x**12/12 + b**5*x**14/14

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